Name of the Post: UPPSC Medical Officer Grade-II 2024 Result Released
Brief Information: Uttar Pradesh Public Service Commission (UPPSC) has given a notification for the recruitment of Medical Officer Grade II, Regional Prohibition and Social Development Officer, Divisional Publication Officer & Regional Tourist Officer/Publicity Officer Vacancy. Those Candidates who are interested in the vacancy details & completed all eligibility criteria can read the Notification & Apply Online.
| Uttar Pradesh Public Service Commission (UPPSC) Adv t No. D-1/E-1/2024 Various Vacancy 2024 onlineform.in | |||
| Application Fee For UR/ EWS/ OBC: Rs.105/- (Application fee : Rs. 80/- + Online Processing fee Rs. 25/-) For SC/ ST : RS. 65/- (Application fee: Rs. 40/- + Online Processing fee Rs. 25/-) For Disabled Category Candidates: RS. 25/- (Application fee: Nil+ Online Processing fee Rs. 25/-) For Ex-Servicemen Candidates: RS. 65/- (Application fee: Rs. 40/- + Online Processing fee Rs. 25/-) Payment Mode: Through Net Banking/ Card Payments/ Other Payment Modes. For More Details Refer the Notification | |||
| Important Dates Starting Date: 15-03-2024 Last Date: 12-04-2024 Last Date for Apply Online: 16-04-2024 Last date for correction/amendment in online Application: 23-04-2024 Last Date for Hard Copy by attaching self-attested photocopies of all educational/medical records: 30-04-2024 | |||
| Age Limit (as on 01-07-2024) Minimum Age Limit: 21 Years Maximum Age Limit: 40 Years i.e. they must have not been born earlier than 2nd July, 1984 and not later than July 01, 2003Age relaxation is Applicable as Per Rules. | |||
| Vacancy Details | |||
| Sl No | Post Name | Total | Qualification |
| 1. | Medical Officer grade-II | 2532 | MBBS/PG Diploma/Degree (Concern Speciality) |
| 2. | Regional Prohibition and Social Development Officer | 01 | Diploma (Journilism)/Any Degree |
| 3. | Prohibition and Social Uplift Officer | 01 | Degree (Economics & Sciology) |
| 4. | Regional Tourist Officer/Publicity Officer | 01 | Degree (Relevant Discipline) |
| Interested Candidates Can Read the Full Notification Before Apply Online | |||
| Important Links |
| Whatsapp Group | Click Here |
| Telegram Group | Click Here |
| Result for Medical Officer Grade-II (21-05-2024) | Link 1 | Link 2 | Link 3 | Link 4 |
| Apply Online | Click Here |
| Detailed Notification | Click Here |
| Short Notification | Click Here |
| Official Website | UPPSC |
How to Download the UPPSC Medical Officer Result 2024?
The result of the UPPSC Medical Officer 2024 is yet to be announced. Download the result from the stepwise guidance mentioned below:
Step 1 – Visit the official website of the Uttar Pradesh PSC.
Step 2 – Under the latest notifications, search for the UPPSC MO 2024 Result Link.
Step 3 – Click on the located link and you will be redirected to a new page.
Step 4 – You can search for your roll number/name in this result sheet by using the “CTRL+F” command on your keyboard.
Step 5 – Also, download the result in PDF format for any future reference.
Details to be Checked in UPPSC Medical Officer Result 2024
The UP Public Commission Medical Officer Result 2024 will hold some important information and guidelines that candidates should look for are:
- Candidates should check their personal information such as name, registration number, date of birth, application number etc.
- Marks obtained by the candidate.
- Candidates should also check if their name is there in the merit list or not. If it is present, then the candidates should go through the guidelines for the next selection process.
How to Calculate Marks for UPPSC Medical Officer Exam 2024?
The marking scheme for the UPPSC Medical Officer Exam 2024 is announced by the UPPSC in their official notification. The written test will be of 150 marks in total and the exam duration will be 120 minutes.
To calculate the marks for the written test, follow the steps given below: –
- Every correct answer carries 1 mark.
- For an incorrect answer, 0.33 marks will be deducted
- So, add up the total number of correct answers and candidates can predict their expected score for the exam.
- Total marks= Total correct answer*1 – Total wrong answer*0.33